Raymond B. answered 12/10/25
Math, microeconomics or criminal justice
200 = 320e^-.051t, solve for t
20/32 =5/8 = e^-.051t
nake natural logs
ln(5/8) = -.051t
t = ln(5/8)/-.051 = about 9.215757
= about 9.2 minutes
rounded to nearest 1 decimal
Genesis C.
asked 03/03/21An element with a mass of 320 grams decays by 5.1% per minute. To the nearest tenth of a minute, how long will it be until there are 200 grams of the element remaining?
Raymond B. answered 12/10/25
Math, microeconomics or criminal justice
200 = 320e^-.051t, solve for t
20/32 =5/8 = e^-.051t
nake natural logs
ln(5/8) = -.051t
t = ln(5/8)/-.051 = about 9.215757
= about 9.2 minutes
rounded to nearest 1 decimal
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