Write in slope intercept form of the equation of the line through the given point through (3,-3) slope =-5/3 show steps

Answer 1

y+3 = (-5/3)(x-3) is the equation of a line with slope -5/3 through the point (3,-3)

y-y1 = m(x-x1) is a formula for an equation with slope = m and through a point (x1, y1)

if m= -5/3 and the point has x1 = 3 and y1 = -3, plug those values into the formula

y- -3 = (-5/3)(x - 3). simplify

y+3 = (-5/3)(x-3) multiply by 3 to eliminate the fraction

3y + 9 =-5x +15

combine constant terms

5x+3y = 6

check it by plugging in the point (3,-3)

5(3) + 3(-3) = 6

15 -9 = 6

for a further check, graph the line and plot the point