Anthony B. answered 09/21/21
Former University Assistant Professor of Electrical Engineering
the discrete time signal is given by: x[n]=3.4cos(0.3πn+1.7)+2.1cos(0.8πn+2.5)
sampling frequency Fs=100 samples/sec, the analog frequencies F1, F2 ∈ [500 550] Hz
digital frequency f is given by: f=F/Fs
0.3/2=F1o/Fs⇒F1o=15 Hz, 0.8/2=F2o/Fs⇒F2o=40 Hz
F1=F1o+kFs, where k=±1, ±2, ⋅⋅⋅, and since F1 ∈ [500 550] Hz ⇒k=5⇒F1=515 Hz
similarly F2=F2o+kFs, F2 ∈ [500 550] Hz ⇒k=5⇒F2=540 Hz
Therefore the corresponding analog signal x(t) is given by:
x(t)=3.4cos(2π515t+1.7)+2.1cos(2π540t+2.5)