
Amy M. answered 03/01/15
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CalTech Grad, Software engineer with 30+ years experience.
The inside rectangle of lawn to be mowed by the other mower will have dimensions
(100-2w)(200-2w)=(100)200/2
where w is the width of the perimeter mowed by the outer mower.
Useing F.O.I.L to expand the above equation
20000-600w+4w**2=10000
4w**2-600w+10000=0
using the quadratic formula to solve for w
w=[600+-sqrt(360000-4(4)10000)]/8
w=75+-25sqrt(5)
w=75+-56
w=19 ft
Discard the positive solution the w we are looking for must be less than 1/2 either dimension (100 or 200)
Check by putting w into the original equation
(100-38)(200-38)=10000
which is half the total area of the 100ftx200ft lawn.