Raymond B. answered 02/24/21
Math, microeconomics or criminal justice
L=2W-7
15 = LW = (2W-7)W = 2W^2 -7W
2W^2 -7W -15 = 0
(2W+3)(W-5) = 0
W = 5 meters
L =2(5)-7 = 3 meters
3 x 5 = 15 square meters
Jane W.
asked 02/24/21The length of a rectangle is 7 less than twice the length of its width. If the area of the rectangle is 15 square meters, find the value of x.
Raymond B. answered 02/24/21
Math, microeconomics or criminal justice
L=2W-7
15 = LW = (2W-7)W = 2W^2 -7W
2W^2 -7W -15 = 0
(2W+3)(W-5) = 0
W = 5 meters
L =2(5)-7 = 3 meters
3 x 5 = 15 square meters
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