Pure acid is to be added to a 20% acid solution to obtain 60 L of a 40% acid solution. What amounts of each should be used? Lof pure acid solution and L of 20% acid solution

Answer 1

100X + 20(60-X) = 40(60) = 2400

100X -20X = 2400-1200

80X = 1200

X = 1200/80 = 120/8 = 15 L of pure acid

60-X - 45 L of 20% acid

20 is within 20 of 40

100 is within 60 of 40

60/20 = 3. You need 3 times as much 20% as 100%, 45 = 3(15)