Daniel B. answered 02/21/21
A retired computer professional to teach math, physics
Notice that points (i), ..., (vi) are approaching x=1 from the right and points
(vii), ..., (xi) are approaching from the left.
The closer is a point Q to x=1, the closer is the slope of the line PQ to the slope of the tangent at x=1.
For this particular function you can treat a pair like (xi),(vi) as an upper and lower
bound on the slope of the tangent.
If you can find a pair (something like Q1=0.999, Q2=1.001) so close to x=1 that the two secant lines PQ1 and PQ2 have identical slopes within two decimal places, then you have your estimate.
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The exact value of the slope at x=1 is -14π.
The thing about this function is that it alternates between up and down extremely quickly.
If I could attach a graph I would; I would recommend that you look at it in some graphing tool.
Just imagine what is happening around x=1:
The argument of sin is 14π, making the value of the function 0.
If you keep increasing x beyond 1, the argument of sin gets smaller;
when the argument of sin gets to 13.5π the value of the function reaches -1
and the direction of the slope reverses.
That means that to get any meaningful estimate of the slope you need x
such that 14π/x is in the interval (13.5π, 14.5π).
That means x must be in the interval (0.97, 1.03).
And you probably need to try values even closer to 1 to get accuracy to 2 decimal digits.
Sofia B.
Hi, thank you so much. What would the answer be because I did (9.8481-7.5575)/2 and got 1.15, but that's apparently wrong. If you could clarify the answer, I would appreciate it. Thank you once again.02/22/21