Mark M. answered 02/17/21
Retired math prof. Very extensive Precalculus tutoring experience.
f(x) = 2x2 - x + 1
[f(a+h) - f(a)] / h = [2(a+h)2 - (a+h) + 1 - (2a2 - a + 1)] / h
= [2(a2 + 2ah + h2) - a - h + 1 - 2a2 + a - 1] / h = (4ah + 2h2 - h) / h = h(4a + 2h - 1) / h = 4a + 2h - 1