The area of the rectangle is x^2+14x+24. Find the length & width (the factors), then determine the perimeter of the rectangle.

Answer 1

x = -14/2 + or - .5sqr(14^2 - 96) = -7 +/- 5 = -12 or -2

Area = 0, length = -2, width = -12, perimeter = -28

maybe this is a rectangle in quadrant 3 where sides are negative

but it still looks like a problem from the twilight zone

Area = A = x^2 +14x +24 = (x+2)(x+12) = 0, x= -2 or -12

Perimeter = 2(L+w) = 2(-2-12)= -2(14) = -28

if factors are the sides then the sides = -2+2 = 0 and -12+12 = 0

0 x 0 = 0 area and perimeter = 0

or let x=0 then area = 24, sides =2 and 12, Perimeter = 28