
Mike D. answered 02/05/21
BSc Mathematics MSc Operational Research
dn/dt = -0.25 and n = 5
We need dc/dt
Differentiate implicitly
cn - 3c - 100n - 100 = 0
c dn/dt + n dc/dt - 3 dc/dt - 100 dn/dt = 0
When n = 5, 5c - 3c - 500 - 100 = 0, so 2c = 600 so c = 300
So substituting in :
300 x -0.25 + 5 dc/dt - 3 dc/dt - 100 x -0.25 = 0
So -75 + 2 dc/dt + 25 = 0
2 dc/dt = 50
dc/dt = 25 pesos per crate per day