Raymond B. answered 01/03/26
Math, microeconomics or criminal justice
L = 4w- 1
P = 48 = 2L +2w
24 = L+w = 4w-1 +w = 5w -1
5w = 25
w = 5 feet wide
L = 4(5)-1 = 19 feet Long
the rectangle is 19 feet by 5 feet
The length of a rectangle is one foot less than four times its width. The perimeter of the rectangle is 48 feet. Find the length and width. Set up and solve using an algebraic equation. Please write a complete sentence answer.
Raymond B. answered 01/03/26
Math, microeconomics or criminal justice
L = 4w- 1
P = 48 = 2L +2w
24 = L+w = 4w-1 +w = 5w -1
5w = 25
w = 5 feet wide
L = 4(5)-1 = 19 feet Long
the rectangle is 19 feet by 5 feet
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