The first of 3 numbers exceed twice the second number by 4, while the third number is twice the first .if the sum of the three numbers is 68, find the numbers.

Question

The sum of three consecutive integers is 51. Find the integers

Answer 1

F=2S + 4, 2S=F-4, S = F/2 - 2

T=2F

F+S+T = 68 or (51? you have 2 different sums?, we'll go with 68)

F + F/2 -2 + 2F = 68

7F/2 = 70

F = 70(2/7) = 20

First = 20, Second = 8, Third = 40

20=2(8)+4

40 =2(20)

and sum of all 3 = 68 = 20+8+40