What is the equation of a line with a slope of 1/2 that contains the point (6,-3)

Answer 1

Using the point slope formula...

(y2- y1)/(x2 - x1) = m (the slope).

Let the second point be arbitrary --> (x,y)

Let the first point be the point of interest --> (6,-3)

Plugging in...

(y - 6)/(x -(-3)) = 1/2

Solving for y gives...

y - 6 = 1/2(x + 3)

y = 1/2*x + 3/2 + 6

y = 1/2*x + 15/2