
Yuri O. answered 01/28/21
16 years online, 464 former SAT problems drilled down
Let “a” be the price of an adult ticket.
Let “c” be the price of a children ticket.
1st way:
12a + 15c = 132 (1)
8a + 11c = 92 (2)
Subract (2) from (1):
4a + 4c = 40
a + c = 10
a = 10 – c
120 – 12c + 15c = 132
3c = 12
c = 4
then a = 10 – 4 = 6
2nd way:
12a + 15c = 132 (1)
8a + 11c = 92 (2)
Divide (1) by “4”:
4a + 5c = 44 (3)
Rewrite (2) as
2(4a + 5c) + c = 92
c = 92 – 2 • 44 = 4
From (3):
4a = 44 – 5 • 4 = 24
a = 6