have that it passes through -5,2 and -1,2 and that it has a vertex of -3,-2

Answer 1

upward opening parabola with vertex (-3,-2) and through (-1,2) and (-5,2)

general formula is y=a(x-h)^2 +k where (h,k) is the vertex

y = a(x+3)^2 -2

plug in either point to solve for "a"

2 = a(-1+3)^2 -2

4 = 4a

a =1

y = (x+3)^2 -2

or

y = x^2 +6x +7