Raymond B. answered 01/03/26
Math, microeconomics or criminal justice
540 - 8(20) = 540- 160 = 380 square meters = area of the path
380 = 2(8x) + 2(20+2x) =20x +40
20x = 340
x = 17 meters = path's width
Damien W.
asked 01/25/21The pool at your campsite measures 8 meters by 20 meters. It is surrounded by a path of uniform width, as shown in the figure. The area of the pool and the path combined is 540square meters.
What is the width of the path?
Raymond B. answered 01/03/26
Math, microeconomics or criminal justice
540 - 8(20) = 540- 160 = 380 square meters = area of the path
380 = 2(8x) + 2(20+2x) =20x +40
20x = 340
x = 17 meters = path's width
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