Tom K. answered 01/23/21
Knowledgeable and Friendly Math and Statistics Tutor
Let x = -2 and evaluate the numerator. We get 3x2 + ax + a + 3 = 3 * 4 -2a + a + 3 = 15 - a
Set this equal to 0.
Thus, a = 15
Now, we have (3x2 + ax + a + 3)/ (x2 + x − 2) =
(3x2 + 15x + 15 + 3)/ (x2 + x − 2) =
(3x2 + 15x + 18)/ (x2 + x − 2) =
3(x2 + 5x + 6)/ (x2 + x − 2) =
3(x + 3)(x +2)/ ((x + 2)(x - 1) )
Then, lim x -> -2 3(x + 3)(x +2)/ ((x + 2)(x - 1) ) =
lim x -> -2 3(x + 3)/ ((x - 1) ) =
3(-2+3)/(-2-1) =
-1