Hector is 54 3 4 inches tall. Joey is 1 1 2 inches shorter than Hector and Jane is 1 1 5 inches shorter than Joey. How tall is Jane?

Answer 1

Hi Zamiiaah M.

First do let me if I have interpreted your fractions correctly

Hector is 54 3/4 inches tall

Joey is 1 1/2 inches shorter than Hector

Jane is 1 1/5 inches shorter than Joey

How tall is Jane?

First we need to know Joey

Joey is

Hector - 1 1/2

54 3/4

- 1 1/2

Must use a least common denominator to subtract, it is 4

54 3/4

- 1 2/4

53 1/4

So Joey is 53 1/4 inches tall

Jane is

Joey - 1 1/5

53 1/4

-1 1/5

You need a least common denominator for 5 and 4 to do the subtraction

Give it a try

Answer 2

Hi...

Clearly Jane is the shortest of the THREE...

Joey's HEIGHT is Hector's height MINUS 1 ¹/₂

54 ³/₄ - 1 ¹/₂

Changing both fractions into MIXED numbers

²¹⁹/₄ - ³/₂

LCD = 8 = 4*2 ....for the numerator cross multiply diagonal each term, subtract the 2nd term from the 1st

[(219)(2) - (3)(4)] / 8

[438 -12]/8

⁴²⁶/₈ ... this is Joey's height (Keep it as a mixed number to use for Jane's height

Jane's HEIGHT is Joey's height MINUS 1 ¹/₅

⁴²⁶/₈ - ⁶/₅

LCD = 40 = 8*5

Use same approach as above to calculate the numerator of this subtraction

[(426)(5) - (6)(8)]/40

[2130 - 48]/40

²⁰⁸²/₄₀...this is Jane's height. Convert it into a MIXED fraction

²⁰⁸²/₄₀ = 52 ²/₄₀ = 52 ¹/₂₀"

OR you can work in decimals; 54.75 - 1.50 = 53.25 - 1.20 = 52.05 = 52 ¹/₂₀"

Hope this helps :)