mary has 200ml of hand sanitizer that is 15% alcohol she mixes it with 200ml of a hand sanitizer that is x% alcohol how many ml of alcohol is in the 2nd hand sanitizer?

Answer 1

.15(200+ x(200)= (400)y

divide by 200

.15 + x = 2y

x = 2y -.15 where y = desired percent of mixture and x = desired percentage of what you mix 15% with

for example, if you want a mixture of 20$ then what percentage should you mix 15% with?

x = 2(.2) -.15 = .4 -.15 = .25 = 25%