How is this solved?

Question

Don Juan Dela Cruz wants to have a fish pond on his backyard with a volume of 240 cubic meters. If the length of the fish pond is three times the width and the height is more than the width, what will be the dimension of the fish pond?

Answer 1

L=3W

H>W

V=240=LWH = 3W(W)H

3W^3 < 240

W^3 < 80

W < 2(cube root of 10) = about 4.3

L< 6(cube root of 10)= about 12.9

H>W> 2(cube root of 10) = about 4.3

Width less than 4.3 feet

Length less than 12.9 feet

Depth more than 4.3 feet

Theoretically, the pond could be a pinhole, nearly zero by zero with depth infinite, but depth is limited by the size of the earth.

Practically, the pond would probably be 1 < W < 4.3

3< L < 12.9

4.3 < D < 80

It could be anywhere from 1x3x80 to 4.3x 4.31 x 12.9