choose 5 objects, without replacement, from 13 distinct objects

Question

Suppose we want to choose 5

objects, without replacement, from 13

distinct objects

How many ways can this be done, if the order of the choices is taken into consideration?

How many ways can this be done, if the order of the choices is not taken into consideration?

Answer 1

13P5 = 13!/(13-5)! = 13!/8! = 13x12x11x10x9= 1287 x 120 = 15,444 permutations if order matters

13C5 = 13!/5!8! = 13x12x11x10x9/5x4x3x2 = 13x11x9 = 1,287 combinations, if order doesn't matter

there are 5! = 120 times as many permutations as combinations for 13 taken 5 at a time