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Question

Two jets leave an air base at the same time and travel in opposite directions. One jet travels 82

 mi/h slower than the other. If the two jets are 11,808 miles apart after 8 hours, what is the rate of each jet?

Answer 1

distance = rate of speed times time

J1 = J2- 82

8J1 + 8J2 = 11808

8(J2-82) + 8J2 = 11808

8J2+8J2 = 11808 + 8(82)

16J2= 11808 +656= 1

J2 = 12464/16 = 3116/4 = 779 mph

J1 = 779-82 = 697 mph