Two jets leave an air base at the same time and travel in opposite directions. One jet travels slower than the other. If the two jets are miles apart after hours, what is the rate of each jet?

Answer 1

J2 = J1-S where S is the mph that the 2nd jet is slower

If they are M miles apart after H hours then

distance - speed times time or M= J2H + J1H = (J1-S)H + J1H = J1H -SH + J1H = 2J1H -SH

2J1H = M+SH

2J = (M+SH)/H = M/H + S = speed of the slower jet

1J = J2+S = speed of the faster jet