write an equation that passes through the points (2, -3) and is parrallel to y=5

Answer 1

y=-3 is the line parallel to y=5 and through the point (2,-3)

y=5 has slope = 0. It's a flat horizontal line

y=mx+b is the general formula for a line with slope =m and y intercept = b

y=(0)x + b

y=0+b

y=b, plug in the point (2,-3) to solve for b

y=(0)x +b

-3=(0)(2) + b

b =-3

the line is

y=(0)x-3

y=-3