Solve this system using the elimination method: y = (1/3)x – 1; 5x = 9y

Question

Solve this system using the elimination method: y = (1/3)x – 1;

5x = 9y

Answer 1

5x=9y

y= (1/3)x-1

5x = 9((1/3)x-1)

5x =3x-9

2x=-9

x =-9/2 =-4.5

x=-4.5

y=(1/3)x -1

y=(1/3)(-9/2)-1 = -3/2-1 = -5/2 = -2.5

y=-2.5

solution = (x,y) = (-4.5,-2.5)

5x=9y

5(-4.5)=9(-2.5)

-22.5 = -22.5

y=(1/3)x-1

-2.5 = (1/3)(-4.5)-1 = -1.5-1 =-2.5