Rahul A.

asked • 12/29/20

regarding function continuous on closed interval

f is said to be continuous in the closed interval [a, b] if

 f is continuous in (a, b)

 lim

x→a+ f (x) = f (a)

 lim

x→b- f (x) = f (b)


the limit at the end points should be defined from both the sides( i.e x→a- and x→b+) i know this is a closed interval but for a limit to exist,it has to be defined from both sides.similarly when we calculate derivative on closed interval this is the condition. why is it so?? can anyone explain?

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Mike D. answered • 12/29/20

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Rahul A.

what about derivatives defined at end points i.e function isdifferentiable on a closed interval [a,b] if it is differentiable on the interior (a,,b) and if the limits below exist at end points.. lim h→0+ f(a+h) - f(a)/h (right hand derivative) at a.... lim h→0- f(b+h) - f(b)/h (leftt hand derivative) at b..... all this till here i have copy pasted from thomas calculus chapter differentiation section 3.2 chapter differentiation. so now here,the limit at the end points should be defined from both the sides( i.e h→0- at a and h→0+ for b) i know this is a closed interval but for a limit to exist,it has to be defined from both sides,(which it isn't defined here) and if limit doesnt exist, how can the derivative exist? why is it so? explain. i have written continuous dots(...) to indicate where the sentence breaks,i tried to write this spaciously but it disorganizes and jumbles up.
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12/29/20

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