Raymond B. answered 01/02/21
Math, microeconomics or criminal justice
L+W+D = 112
L= -32 + W+ D
2W = 4+ L
by substitution eliminate 2 variables and solve for the 3rd
D=L+32-W
W = 2+L/2
L + 2+ L/2 + L +32 - 2+L/2 = 112
2L = 112 -32 = 80
L = 80/2 = 40
W = 2+ 40/2 = 22
D = 40+ 32 -22 = 50
LxWxD = 40x22x50
40+22+50= 112
B is correct
(A is close, C and D off the mark)