A full-wave rectifier is connected to a sinusoidal waveform with an amplitude of 10V and a load resistor of 1k ohms. What is the Vrms of the circuit?

Answer 1

If you mean the RMS value of the output voltage, we first start with the peak value of 10V and subtract from that the two voltage drops across the 2 diodes that will conduct in each half-cycle to get Vopeak (the voltage across the 1K resistor as your load). Assuming VDo = 0.7V for each diode, Vopeak = 10 -1.4 = 8.6V which will result in Vorms = Vopeak/sqrt(s) = 8.6/sqrt(2) = 6.1 V. Note that I am assuming that you are talking about the bridge full-wave rectifier.