
Bradford T. answered 12/15/20
Retired Engineer / Upper level math instructor
This is what we like to call in algebra "Dirt" problems, or distance = rate x time. (drt)
Time is constant for both the train and the car. Let x = the average speed of the car, so we first need to solve for time and then set both the equations together.
t = distance/rate.
450/x = 350/(x-20) --> the car distance divided by the car speed equals the train distance divided by the train speed which is 20 km/h slower than the car's speed.
Dividing both sides by 450 and multiply by x-20:
(x-20)/x = 350/450
1 - 20/x = 7/9
Multiply both sides by x
x-20 = 7x/9
2x/9 = 20
x = (9/2)20 = 180/2 = 90 km/h