calculate the equation of the line parallel to y=2/3x+8 and passing through the point (6,-1)

Answer 1

Hello,

equation of a straight line is y = m x + b

the slope of parallel lines are equal, therefore the slope of the line is also 2/3.

so far we have y = 2/3 x + b

to find b or y-intercept, plug in the coordinates (6, -1)

-1 = 2/3 * 6 + b

-1 = 12/3 + b

-1 = 4 + b

isolate b

-1 - 4 = b

-1 + - 4 = b

-5 = b

therefore, the equation of the line parallel to y=2/3x+8 and passing through the point (6,-1) is

y = 2/3 x - 5