Write an equation in point-slope form for the line parallel to y=5x-4 that contains P(-6,1)

Answer 1

The slope of the given line is 5.

The slope of the new parallel line must be 5 also.

Passsng through (-6,1) in point slope form

y- y₁= 5 (x - x₁)

y -1 = 5(x - (-6))

y= 5x + 31 is the equation of the line.

b=31

The equation of the line is

y= 5x + 31

Answer 2

all parallel lines have the same slope

y=5x + b, plug the point into that equation to solve for b, the y intercept

1 =5(-6) + b

b = 31

y=5x+31 is in slope y intercept form

y-31 = 5x or

y-31 = 5(x-0) is in point slope form, using the point (0,31) and slope = 5

or use the given point (-6,1) to get

y-1 =5(x+6) which is also in point slope from and is equivalent to y-31=5x