find three consecutive odd integers such that the smallest integer increased by 23 is equal to the sum larger two

Question

Find three consecutive odd integers such that the smallest integer increased by 23 is equal to the sum of the larger two

Answer 1

Let the 3 consecutive odd integers be X, X + 2 and X + 4

 

The smallest increased by 23 is equal to the sum of the larger 2  ==>  

 

X + 23 = (X+2) + (X+4)

x + 23 = 2X + 6

X = 17

 

So the 3 consecutive odd integers are 17, 19 and 21 

 

Check :  17 + 23 = 40

             19 + 21 = 40