Inactive Tutor answered 12/07/20
Tutor
New to Wyzant
a. We must use the trig identity cos(2x) = (-1 + 2cos2(x))
cos(2arccos(2/5))
= -1 + 2cos2(arccos(2/5))
= -1 + 2(2/5)2
= -17/25
Cel R.
asked 12/07/20Give the exact value of each expression without using a calculator.
(a) 𝑐𝑜𝑠(2𝑐𝑜𝑠^ −1(2/5))
(b) 𝑠𝑖𝑛(𝑐𝑜𝑠^ −1(1/3)+𝑡𝑎𝑛^ −1(2))
Inactive Tutor answered 12/07/20
a. We must use the trig identity cos(2x) = (-1 + 2cos2(x))
cos(2arccos(2/5))
= -1 + 2cos2(arccos(2/5))
= -1 + 2(2/5)2
= -17/25
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