find width and length

Question

The length of a rectangle is 2 meters longer than the width. If the area is 29 square​ meters, find the​ rectangle's dimensions. Round to the nearest tenth of a meter.

Answer 1

This question is not elementary math but elementary algebra.

Answer 2

area of a rectangle is length (l) * width (w)

l = w + 2

so area = l ( l + 2) = 29

l^2 + 2l = 29

l^2 + 2l - 29 = 0

use the quadratic formula for solve for l, accepting only the negative solution

quadratic formula:

x = -b +/- sqrt(b^2 - 4ac)/2a, where a = 1, b = 2, c = -29