Please help me with this question....

Question

Write the equation of a line that is perpendicular to the line x +3y = 16 and passes through the point (-3, -4)

Answer 1

Write the equation of a line that is perpendicular to the line x +3y = 16 and passes through the point (-3, -4)

1. since you are looking for a "perpendicular line", its slope has to be -1/slope of the original line (m1) and since the original line is y = (-1/3)x + 16/3, then m1 = -1/3 and m2 is 3 giving you y - y0 = 3(x - x0),
2. where y + 4 = 3(x + 3)
3. or y = 3x + 5;