y^2+x^2=y^4-2x ..
2yy'+2x=4y^3y'-2
y'=-2*(x+1)/(2y-4y^3)
y'=1 (x=0,y=1)
Anna L.
asked • 11/24/20Calcukus Question (Implicit Differentiation)
Find the equation of tangent line to the curve y²+x² = y⁴ - 2x at y=1 and x=0
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