William W. answered 11/22/20
Math and science made easy - learn from a retired engineer
The first term is when n = 1
a1 = (-1)1+1(1 + 6)
a1 = (-1)2(7)
a1 = (1)(7) = 7
The second term is when n = 2:
a2 = (-1)2+1(2 + 6)
a2 = (-1)3(8)
a2 = (-1)(8) = -8
The third term is when n = 3
a3 = (-1)3+1(3 + 6)
a3 = (-1)4(9)
a3 = (1)(9) = 9
The fourth term is when n = 4:
a4 = (-1)4+1(4 + 6)
a4 = (-1)5(10)
a4 = (-1)(10) = -10