A man has $270,000 invested in three properties. One earns 12%, one 10% and one 8%. His annual income from the properties is $25,800 and the amount invested at 8% is twice that invested at 12%.

Question

A man has $270,000 invested in three properties. One earns 12%, one 10% and one 8%. His annual income from the properties is $25,800 and the amount invested at 8% is twice that invested at 12%.

(a) How much is invested in each property?

12%	property	$
10%	property	$
8%	property	$

(b) What is the annual income from each property?

12%	property	$
10%	property	$
8%	property	$

Answer 1

.08(2x) + .10(270,000 -3x) +.12x = 25,800

.- .02x = 25800 -27000 =-1200

x = -1200/-.02 = $60,000 at 12%.

$120,000 at 8%

270,000 - 3x = $ 90,000 at 10%

annual income from the 10% investment = $9,000

and annual income from other two is $16,800

with annual income from 12% at 1/3 that = $5,600

and annual income from 8% at $11,200