Factor the trigonemetric expression: cot^2(x) + cscx - 1

Question

How do I go about factoring this trigonometric expression. I am quite confuseed.

Answer 1

use the identity cot^2 = csc^2-1

csc^2(x) -1 -csc (x)- 1=

csc^2(x)-csc(x) - 2 this factors to

(csc(x)-2)(csc(x)+1)