What is the formula for a quadratic function whose graph has a vertex (-2,4) and y intercept 5

Answer 1

y = a(x+2)^2 +4, plug in (0,5) to solve for "a"

5 = 4a +4

4a = 1

a = 1/4

y = .25(x+2)^2 +4 is the equation of an upward opening parabola