
Yefim S. answered 11/07/20
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s = ∫24(1 + y'2)1/2dx = ∫24(1 + x2/(16 - x2))1/2dx = ∫244/(16 - x2)1/2 = 4sin-1(x/4)24 = 4sin-11 - 4sin-11/2 = 4π/3.
s = 4π/3
Yefim S. answered 11/07/20
Math Tutor with Experience
s = ∫24(1 + y'2)1/2dx = ∫24(1 + x2/(16 - x2))1/2dx = ∫244/(16 - x2)1/2 = 4sin-1(x/4)24 = 4sin-11 - 4sin-11/2 = 4π/3.
s = 4π/3
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