through (-2,-3), parallel to y=5/2x - 2

Answer 1

In this problem it would be easiest to use point slope form.

The general formula for point slope form is:

y - y0 = m (x - x0)

where m is the slope, and the point you are going through is (x0, y0).

Since this graph needs to be parallel to y = (5/2)x - 2, the slopes must be equal.

Therefore, m = 5/2.

Since the point we are going through is (-2, -3), x0 and y0 are -2 and -3 respectively.

If we plug in this information, we get:

y - (-3) = (5/2) * (x - (-2))

This simplifies to:

y + 3 = (5/2) * (x + 2)

This is our equation, however if you need to get into y = mx + b form, you do the following:

First, distribute the 5/2:

y + 3 = (5/2)x + 5

Next, subtract 3 on both sides to isolate y:

y = (5/2)x + 2

So, our answer is y = (5/2)x + 2

or y + 3 = (5/2) * (x + 2) if you want point slope form