Raymond B. answered 01/08/26
Math, microeconomics or criminal justice
w = kd^4/h^2
1 = k(2)^4/8^2 = k(16)/64 = k/4
k = 4(1) = 4
w = 4d^4/h^2
w =4(1^4)/4^2 = 4(1)/16 = 1/4 ton
Ka L.
asked 11/03/20The maximum weight that a circular column can support is directly proportional to the fourth power of it's diameter and is inversely proportional to the square of it's height. A 2-meter -diameter column that is 8 meters in height can support 1 ton. Find the weight that a 1-meter diameter column that is 4 meters in height can support.
Raymond B. answered 01/08/26
Math, microeconomics or criminal justice
w = kd^4/h^2
1 = k(2)^4/8^2 = k(16)/64 = k/4
k = 4(1) = 4
w = 4d^4/h^2
w =4(1^4)/4^2 = 4(1)/16 = 1/4 ton
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.