
Patrick B. answered 11/05/20
Math and computer tutor/teacher
(part A)
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f(t) = K * e^(kt)
f(0) = 300 ---> k = 300
so f(t) = 300 * exp(kt)
(4, 240) ---> 240 = 300*(e^4k)
240/300 = (e^4k)
4/5 = e^(4k)
ln 4/5 = 4k
(ln 4/5)/4 = k
(1/4)(ln 4/5) = k
f(t) = 300 * exp( (ln 4/5) (t/4))
= 300 * (exp (ln 4/5) )^(t/4)
= 300 * (4/5)^(t/4)
part (B)
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Half life : 1/2 = (4/5)^(t/4)
ln(1/2) = (t/4) ln (4/5)
-ln2 = (t/4) (ln 4 - ln 5)
-4 ln 2 / (ln 4 - ln 4) = t
part (C)
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f(24) = 300 * (4/5)^6 = 78.6432