
Conrad D. answered 11/11/20
Engineering and Math tutor
d y / d t = y (20 - y ) / 2
d t = 2 d y / [ y ( 20 - y ) ]
1 / 10 [ 1/y + 1 / ( 20 - y ) ] d y = d t
l n [ y ( 29 - y ) ] = 10 t + C1
1 / 10 [ ( l n ( 1 / y ) ] + [ 1 / l n ( 20 - y ) ] = t + C1
y ( 20 - y ) = e ^ 10 t + C1
y ( 20 - y ) = e ^ C1 e ^ 10 t
y ( 20 - y ) = K e ^ 10 t
none of the above