Graphing it you can see that the function is not continuous; it has a jump at x = 1:
If you plug in x = 1 to the "2x + 2" you get f(1) = 4. And the limit as x approaches 1 from the left is -2 (the value of "x2 - x - 2" at x = 1 is -2).
Ahmad S.
asked 11/02/20f(x)= {x^2-x-2/x+1 where x<-1
2x+2 where x>or equal to -1}
Graphing it you can see that the function is not continuous; it has a jump at x = 1:
If you plug in x = 1 to the "2x + 2" you get f(1) = 4. And the limit as x approaches 1 from the left is -2 (the value of "x2 - x - 2" at x = 1 is -2).
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.