Find three consecutive odd integers such that the difference of twice the second and the first is 13

Answer 1

9,11,13 are the numbers,, = f,s, t, ...

2(11) - 9 = 22-9=13

2s -f =13, s=second, f=first

twice 2nd minus 1st = 13

1st is 2 less than the 2nd

f=s-2

2s -(s-2) = 13

2s -s+2 =13

s = 11

the numbers are 9, 11, 13,

2(11)-9 =22-9=13