Calculus II Integration by parts

Question

∫6ln(x²-1)dx

Answer 1

∫6ln(x² - 1)dx = 6xln(x² - 1) - ∫6x·2x/(x² - 1)dx = 6xln(x² - 1) - ∫[12 + 12/(x² - 1)]dx = 6xln(x² - 1) + 12x +

+ 6 ln[(x-1/(x + 1)] + C.

We use integration by parts formula