Mark M. answered 10/24/20
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
If f(x) had a relative min at x = -1.5, then f'(x) would change sign from negative to positive there. Since that is not the case, there is no relative min at x = -1.5.
When x < -3.2, f'(x) < 0. So, f is decreasing there.
To the left of x = -1.5, f'(x) is increasing, so (f')'(x) = f"(x) > 0. To the right of x = -1.5, f'(x) is decreasing, so f"(x) < 0. Since f"(x) changes sign when x = -1.5, the function y = f(x) has an inflection point at x = -1.5.