A chemist needs 100 milliliters of a 48% solution but has only 32% and 52% solutions available. Find how many milliliters of each that should be mixed to get the desired solution.

Answer 1

100(.48 = ..52x + ..32(100-x)

solve for x = mgs of 52%

100-x = mgs of 32%

48 = .2x +32

.2x = 16

x = 16/.2 = 80 mg

100-x = 20 mg

52-48 = 4

48-32 = 16

16/4 = 4 times as much 52% needed as 32%

x + x/4 = 100

5x = 400

x = 400/5 = 80 mgs of 52% 20 mgs of 32%